Question

How do you solve `log_x(1/8) = -3/2`?

Answer 1

`x=4`

Explanation:

`log_x(1/8)=-3/2`

`log_x 2^(-3) = -3/2`

`-3log_x 2 = -3/2`

`log_x 2=1/2`

`2= x^(1/2)`

`x=4`