Question

What fraction of the volume of an ice berg is visible above ocean water ? (density of ice =917) (density of water =1025)

Answer 1

`0.105`

Explanation:

According to Archimedes principle,

Weight of iceberg = Bouyant Force

`"m"_i cancel"g" = "m"_w cancel"g"`

Here

• `"m"_i =` Mass of iceberg
• `"m"_w =` Mass of water displaced

`"V"_i "d"_i = "V"_w "d"_w color(white)(..)[∵ "Mass = Volume × Density"]`

Volume of water displaced (`"V"_w`) = Volume of iceberg inside the water

or

Volume of water displaced (`"V"_w`) = Volume of iceberg (`"V"_i`) - Volume of iceberg visible (`"V"`)

`"V"_i "d"_i = ("V"_i - "V") "d"_w`

`"V"_i "d"_i = "V"_i "d"_w - "V" "d"_w`

`"V"/"V"_i = ("d"_w - "d"_i)/"d"_w = ("1025 kg/m"^3 - "917 kg/m"^3)/("1025 kg/m"^3) = color(blue)(0.105)`