How do you simplify #4 + 6 (ac +2b) + 2ac#?

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Answer 1 · 2018-04-17T19:30:26

see a solution process below

#4 + 6(ac + 2b) + 2ac#

remove the bracket;

#4 + 6ac - 12b + 2ac#

collect like terms;

#4 + 6ac + 2ac - 12b#

simplifying;

#4 + 8ac - 12b#

factorizing the common factor;

#4(1 + 2ac - 3b)#

simplified