Please solve q 42?

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Answer 1 · 2018-04-18T12:14:22

The answer is #"option (B)"#

Let the number of diamonds robbed be #=x#

To the first watchman, he gave

#(x/2+2)# and the number remaining is #(x/2-2)#

To the second watchman, he gave

#(1/2(x/2-2)+2=x/4+1)# and the number remaining is #(1/2(x/2-2)-2=x/4-3)#

To the third watchman, he gave

#(1/2(x/4-3)+2=x/8+1/2)# and the number remaining is #(1/2(x/4-3)-2=x/8-7/2)#

But,

#x/8-7/2=1#

#x/8=1+7/2=9/2#

#x=9/2*8=36# diamonds

The answer is #"option (B)"#