How to integrate #intx/(cos^2 (x^2))dx# ?
#intx/(cos^2 (x^2))dx#
3 Answers
see below
Explanation:
We have,
Substituting
Putting this value in the main integral,we get,
Or,
Or,
Explanation:
The integral is equal to
Explanation:
Let
#I = int 1/(2cos^2u) du#
#I = 1/2int sec^2u du#
This is a known integral
#I = 1/2tanu + C#
Reverse the substitution
#I = 1/2tan(x^2) +C#
Hopefully this helps!