How many atoms are in 167 g of calcium?

2 Answers
Apr 18, 2018

remind that mass=number of moles x molar mass and molar mass of Ca is 40
167=n*40
n=4.175
1 moles =6.02 × 10^23 atoms
therefore 4.1752 moles of Ca=4.175*6.02 × 10^23 =2.51335× 10^24 atoms

Apr 18, 2018

m=167g
M(Ca)=40.078g/(mol)

Explanation:

n=m/M=167g/(40.078 g/(mol))=4.167 mol
n-numbers of mol

N=n*N_a=4.167 mol*6,022 × 10^(23) (atoms)/(mol)
=25*10^(23) atoms

N_a- Avogadro's constant=6,022 × 10^(23) (atoms)/(mol)