How do you multiply #(y-7)(y+7)#?

Question

4355 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-19T07:26:40

#y^2-7^2#

So here can apply a index rule which is:

#(a+b)(a-b)=a^2-b^2#

So we just apply these brackets to get:

#(y-7)(y+7)#

Simplify:

#y^2+7y-7y-7^2#

Simplify:

#y^2-7^2#

Hope this helps!