Question

How do you write the equation in standard form 5y-1/3x=-8?

Answer 1

`y=(24x+1)/5`

Explanation:

`(5y-1)/(3x)=8`
`(5y-1)=8(3x)`
`5y-1=24x`
`5y=24x+1`
`y=(24x+1)/5`

The standard form for a linear equation is in the form `y=x+b`, therefore, we want to isolate y. To do this, first, we want to get rid of the denominator, which is done by multiplying both sides of the equation by `3x`. The denominator would cancel out on the left side. Then add `1` to both sides of the equation to remove it from the left side. After isolating `5y`, `y` can be isolated by dividing both sides by `5`. This gives the answer, `y=(24x+1)/5`.

Answer 2

`x-15y=24`

Explanation:

`"the equation of a line in "color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))`

`"where A is a positive integer and B, C are integers"`

`"multiply all terms by "-3`

`rArr-15y+x=24`

`rArrx-15y=24larrcolor(red)"in standard form"`