Two corners of an isosceles triangle are at (2,4) and (3,8). If the triangle's area is 48, what are the lengths of the triangle's sides?

1 Answer
Apr 19, 2018

Lengths of the sides of the triangle are

a=b=23.4,c=4.12

Explanation:

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A(2,4),B(3,8), Area At=48, To find AC, BC

AB=c=(23)2+(48)2=4.12

At=(12)(AB)(CD)

CD=h=2484.12=23.3

Applying Pythagoras Theorem,

AC=BC=b=h2+(c2)2

b=23.32+(4.122)2=23.4

a=b=23.4,c=4.12