Question

Please solve q 61?

Answer 1

The magnitude of the acceleration is `F_1/m`

Explanation:

The three forces acting together kept the particle in equilibrium. Thus, there resultant was zero. So

`vec{F}_1+ vec F_2+vec F_3 = 0`

When the force `vec F_1` is removed, the net force is

`vec F_2 + vec F_3 = -vec F_1`

Thus the acceleration is

`vec a = - (vec F_1)/m qquad implies qquad |vec a| = |vec F_1|/m`