How do you convert #(-3, 3)# into polar coordinates?

1 Answer
Apr 20, 2018

#(-3,3)to(3sqrt2,(3pi)/4)#

Explanation:

#"to convert from "color(blue)"cartesian to polar"#

#"that is "(x,y)to(r,theta)" where"#

#•color(white)(x)r=sqrt(x^2+y^2)#

#•color(white)(x)theta=tan^-1(y/x);-pi< theta<= pi#

#"here "x=-3" and y=3#

#rArrr=sqrt((-3)^2+3^2)=sqrt18=3sqrt2#

#(-3,3)" is in the second quadrant so "theta" must be in the "#
#"second quadrant"#

#theta=tan^-1(1)=pi/4larrcolor(red)"related acute angle"#

#rArrtheta=pi-pi/4=(3pi)/4larrcolor(red)"in second quadrant"#

#rArr(-3,3)to(3sqrt2,(3pi)/4)#