What is the cross product of #<3 ,1 ,-6 ># and #<-2 ,1 , 8 >#?

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Answer 1 · 2018-04-20T16:22:55

# <14,-12,5>#

we want

#<3,1,-6>xx<-2,1,8>#

this is found by calculating the determinant

#|(hati,hatj,hatk),(3,1,-6),(-2,1,8)|#

expand by row 1

#hati|(1,-6),(1,8)|-hatj|(3,-6),(-2,8)|+hatk|(3,1),(-2,1)|#

#=hati(8 --6)-hatj(24- 12)+hatk(3- -2)#

#14hati-12hatj+5hatk#

#= <14,-12,5>#