Question

A cube of wood floating in water supports a 200-g mass resting on the center of its top face.when the mass removed the cube rises 2-cm.determine the volume of the cube? Ans: 1000 cm^3

Answer 1

`"1000 cm"^3`

Explanation:

Let edge length of cube be `"x cm"`

Volume of water displaced by `"200 g"` object is `2"x"^2\ "cm"^3`

`"Mass of 200 g block = Mass of water displaced"`

`"200 g = V d"`

`200 cancel"g" = "2x"^2cancel("cm"^3) × 1 cancel"g""/"cancel("cm"^3)`

`x = sqrt(200/2) = 10`

Volume of cube`= "(edge length)"^3 = "(10 cm)"^3 = "1000 cm"^3`