Question

How do I evaluate `int_0^pisin(x)dx?`

Answer 1

`2`

Explanation:

Given: `int_0^pisin(x) \ dx`.

`=[-cos(x)]""_0^pi`

`=-cos(pi)-(-cos(0))`

`=-cos(pi)+cos(0)`

`=-(-1)+1`

`=1+1`

`=2`