Question

How do you solve for a in `x= -b/2a`?

Answer 1

`(2x)/(-b)=a`

Explanation:

You have to reverse the mapping, so first multiply both sides by 2 this will remove it from the RHS (right hand side)

`color(red)2x=-color(red)2b/color(red)2a`

`2x=-ba`

Divide by negative b or `-b`

`(2x)/color(red)(-b)=color(red)(-b)/color(red)(-b)a`

`(2x)/(-b)=a`