Question

Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for `log(80)`?

Answer 1

0.82

Explanation:

we need to know the log property

`loga*b=loga+logb`

`log(80)=log(8*10)=log(8*5*2)=log(4*2*5*2)=log(2*2*2*5*2)`

`log(2*2*2*5*2)=log2+log2+log2+log5+log2=4log2+log5`

`4*(0.03)+0.7=0.12+0.7=0.82`