The oxidation number of sulphur in sulphuric acid h2so4 is?

2 Answers
Apr 23, 2018

+6

Explanation:

O.N of Oxygen= -2
O.N of Hydrogen= +1
O.N of Sulphur= x(say)

Now,

2(1)+x+4(-2)=0
x-6=0
x=6

Thus, O.N. of Suplhur is 6

Apr 23, 2018

+6

Explanation:

In H_2SO_4, hydrogen exists in its usual +1 state, and oxygen exists in its -2 state.

Let x be the oxidation number of sulfur in sulfuric acid. Then we got:

1*2+x-2*4=0

2+x-8=0

x-6=0

x=6

So, sulfur exists in the +6 state.