Quadratics question?

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1 Answer
Apr 23, 2018

From the unchanging zeros and the halving of the height, it appears # g(x) = 1/2 f(x) #, choice b.

Explanation:

When we scale the argument, like in #f(2x)# or #f(x/2)#, that stretches or compresses in the #x# direction, which isn't happening here.

When we scale like #1/2 f(x)# or #2 f(x)# that compresses or stretches in the #y# direction. That seems like what's going on.

The function is unchanged when #f(x)=0# (around # x=-8# and #x=0#) which is consistent with #y# scaling.

The height at the apex at #x=4# went from #3# to #3/2# indicative of a #y# scale factor of #1/2#. That looks right in general.

So it appears # g(x) = 1/2 f(x) #, choice b.