How do you decide whether the relation #x^2 + y^2 = 1# defines a function?

1 Answer
Apr 23, 2018

#x^2+y^2=1# does not describe a function because there exist valid values of #x# for which more than one value of #y# make the equation true.

Explanation:

Let's write this equation in a different form.

#y^2-(1-x^2)=0#.

Now think of it like the difference of two squares and write this as the product of two binomials.

#(y-sqrt(1-x^2))(y+sqrt(1-x^2))=0#

Note that there are TWO solutions for #y# here, namely

#y=sqrt(1-x^2)#, and #y=-sqrt(1-x^2)#.

This relation is NOT a function. In order for an equation to represent a function, every #x# in the range of the function must only have one #y#-value.