Question

How do you solve for b in `d = 3a + 3b`?

Answer 1

`=>b = d/3 - a`

Explanation:

We are given

`d = 3a + 3b`

Subtract `3a` from both sides

`d - 3a = 3a + 3b - 3a`

`d - 3a = cancel(3a)+3b cancel(-3a)`

`d - 3a = 3b`

Divide both sides by `3`

`(d-3a)/3 = (3b)/3`

`d/3 - (cancel(3)a)/cancel3 = (cancel(3)b)/cancel3`

`d/3 - a = b`