Question

How do you solve `x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0`?

Answer 1

so with this equation you can see that the factors are
`(x^2-49)` and `(x^2-64)`

from there, set both factors equal to 0

`x^2-49=0`
add 49 to both sides
`x^2=49`
square root
`sqrtx=sqrt49`
`x=7`

same process for the other one, square root of 64 is 8, etc

so

`x={7,8}`