Question

How do you find the perimeter of a triangle when the sides are `4, 12, and sqrt28`?

Answer 1

You add them all. The answer is 16 + `2sqrt(7)`

Explanation:

You factor out the `sqrt(28)`, and it becomes `2sqrt(7)`. With this, you add this to 4 and 12. You end up getting 16 + `2sqrt(7)`.