Please help!?

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1 Answer
Apr 24, 2018

#37#

Explanation:

Well, if #B# is the centre of the circle, then it will intersect chord #AC# at the midpoint of it, which is #D#, and #BD# becomes the perpendicular bisector of #AC#.

So, we have get #/_ADB=90^@#.

Looking at #DeltaADB, /_ADB=90^@,/_DAB=53^@#.

Therefore, the measure of #/_ABD# will be:

#/_ABD=180^@-/_ADB-/_DAB#

#=180^@-90^@-53^@#

#=90^@-53^@#

#=37^@#

Since you want the answer without the units, we can leave out the degrees sign, and the numeric answer will be #mathbb(37)#.