Cos 3 theta/sin 3 theta?

2 Answers
Apr 26, 2018

cot3thetacot3θ

Explanation:

Using the identity cottheta = costheta/sinthetacotθ=cosθsinθ, we know that (cos3theta)/(sin3theta)cos3θsin3θ = cot3thetacot3θ

Apr 26, 2018

(cos 3t)/(sin 3t) = cot (3t)cos3tsin3t=cot(3t)

Trig books give:

cot 3t = (3cot t - cot^3 t)/(1 - 3cot^2 t)cot3t=3cottcot3t13cot2t