Differentiate y=x^2+5x+3?

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Answer 1 · 2018-04-27T06:50:24

#2x+5#

Given: #y=x^2+5x+3#.

Differentiate using the power rule, #d/dx(a^x)=xa^(x-1),x!=-1# and the constant rule, #d/dx(a)=0,ainRR#.

We get:

#y'=2x+5+0#

#=2x+5#

Answer 2 · 2018-04-27T06:51:22

#d/dx (x^2+5x+3)= 2x+5#

Derivative of any polynomial #x^a = a*x^(a-1)#.

Using this formula with the sum rule gives us-

Derivative of #x^2+5x+3 = d/dx(x^2)+d/dx5x +d/dx3#

=#2x + 5 + 0 #(derivative of constant is 0)

=#2x + 5#