How do you simplify #sqrt(5.6)#?
1 Answer
Apr 27, 2018
Explanation:
#"using the "color(blue)"laes of radicals"#
#•color(white)(x)sqrtaxxsqrtb=sqrt(ab)" and "sqrtaxxsqrta=a#
#•color(white)(x)sqrt(a/b)=sqrta/sqrtb#
#"note that "5.6=56/10#
#rArrsqrt5.6=sqrt(56/10)=sqrt56/sqrt10#
#"and "sqrt56=sqrt(4xx14)=sqrt4xxsqrt14=2sqrt14#
#rArrsqrt56/sqrt10=(2sqrt14)/sqrt10#
#color(blue)"rationalise the denominator"#
#"multiply numerator/denominator by "sqrt10#
#rArr(2sqrt14)/sqrt10xxsqrt10/sqrt10#
#=(2sqrt140)/10=(2xx2sqrt35)/10=(4sqrt35)/10=2/5sqrt35#