How do you factor #ac - 3ad - 2bc + 6bd#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Evan Apr 27, 2018 #(a-2b)(c-3d)# Explanation: #ac-3ad-2bc+6bd# Factorise #a# out of the first two terms, and #-2b# out of the last two terms, #a(c-3d)-2b(c-3d)# Factorise #(c-3d)# from both terms, #(a-2b)(c-3d)# Tadaaa :D Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 2567 views around the world You can reuse this answer Creative Commons License