What is #2 7/8 -: 5/6#?

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Answer 1 · 2018-04-27T15:54:06

#69/20#

In order to divide fractions, we must first convert each term into an improper fraction:

2#7/8# = #23/8#

Next, we must reciprocate the divisor by swapping the numerator and the denominator and multiply the dividend and the reciprocated divisor:

#23/8# x #6/5# = #138/40#

Finally, we simplify the fraction by dividing the numerator and the denominator by their greatest common factor (2):

#(138/2)/(40/2)# = #69/20#

Answer 2 · 2018-04-27T15:55:42

#=3 9/20#

Change mixed numbers to improper fractions first:

#2 7/8 div5/6#

#=23/8 div 5/6#

#= 23/8 xx 6/5" "larr# simplify by cancelling first

#= 23/cancel8_4 xx cancel6^3/5#

#=69/20#

#=3 9/20#

Answer 3 · 2018-04-27T15:58:27

#69/20=3 9/20#

#2 7/8-:5/6#

#23/8-:5/6#

#23/8*6/5#

#69/20=3 9/20#

Convert the mixed number to an improper fraction. In this case, #2 7/8# is the mixed number, so convert that to an improper fraction, which would be #23/8#
Divide the fractions by multiplying by the reciprocal of the second term. In this case the second term is #5/6#. So, you would multiply #23/8# by #6/5# to get the answer.
Convert the final answer to a mixed number if necessary.