How do you solve #x = 2y - 2# and #3x - y = 14# using substitution?
1 Answer
Apr 27, 2018
Explanation:
#x=2y-2to(1)#
#3x-y=14to(2)#
#"equation "(1)" expresses x in terms of y"#
#color(blue)"Substitute "x=2y-2" into equation "(2)#
#rArr3(2y-2)-y=14#
#rArr6y-6-y=14#
#rArr5y-6=14#
#"add "6" to both sides"#
#rArr5y=20rArry=20/5=4#
#"substitute "y=4" into equation "(1)#
#rArrx=(2xx4)-2=6#
#"the point of intersection of the 2 equations "=(6,4)#
graph{(y-1/2x-1)(y-3x+14)((x-6)^2+(y-4)^2-0.04)=0 [-10, 10, -5, 5]}