How do you multiply and simplify #\frac {x^2 + 6x + 8} { x^2- 5x + 4} \cdot \frac { x ^ { 2} + 3x - 4} { x ^ { 2} + 4x + 4}#?

1 Answer
Apr 27, 2018

#((x+4)^2)/((x-4)(x+2))#

Explanation:

Okay, so first things first: Factor.

You're going to want to factor the equations, from there, you can simplify. So, factor each numerator and denominator. You should get:

#(((x+4)(x+2))/((x-4)(x-1)))#*#(((x+4)(x-1))/((x+2)(x+2)))#

From here, you can see how terms cancel and combine. So, you can tell that one #x+2# will cancel and the #x-1#'s will cancel, and the #x+4#'s will combine into #(x+4)^2#.

Then you'll have:
#((x+4)^2)/((x-4)(x+2))#

And there you have your final answer!