How do you solve #5x + 5= 3( x - 3)#?

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Answer 1 · 2018-04-28T13:46:59

#x=-7#

Isolate the variable:

#5x+5=3(x-3) rarr# Use the distributive property

#5x+5=3*x-3*3#

#5x+5=3x-9#

#5x+14=3x#

#14=-2x#

#x=-7#

Answer 2 · 2018-04-28T13:47:26

#x=-7#

#5x+5=3(x-3)#

#rArr 5x+5=3x-9#

#rArr 2x=-14#

#:. x=-7#

Hope this helps :)