What is the slope of the line between $(- 2, - 32)$ $(-2,-32)$ and $(6, 0)$ $(6,0)$ ?

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Answer 1 · 2018-04-28T21:50:20

4

the slope $m$ $m$ can be given through the relation

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}} = m$ $(y_2-y_1)/(x_2-x_1)=m$

You can assume any point to be $(x_{1}, y_{1})$ $(x_1,y_1)$ and the other will be

$(x_{2}, y_{2})$ $(x_2,y_2)$

$(x_{1}, y_{1}) = (- 2, - 32)$ $(x_1,y_1)=(-2,-32)$

$(x_{2}, y_{2}) = (6, 0)$ $(x_2,y_2)=(6,0)$

$\frac{0 - (- 32)}{6 - (- 2)} = 4$ $(0-(-32))/(6-(-2))=4$

The straight lines slope $(m) = 4$ $(m)=4$

What is the slope of the line between (-2,-32) (−2,−32) (-2,-32) and (6,0) (6,0) (6,0) ?