How do you solve #5e^(2x) = 500#?

1 Answer
Apr 29, 2018

#x=ln(100)/2#

Explanation:

We can start off by dividing both sides by #5#. We get

#e^(2x)=100#

We can take the natural log of both sides to cancel out base #e#. We get

#ln(e^(2x))=ln(100)#

#=>2x=ln(100)#

#x=ln(100)/2#

I chose to not evaluate #ln(100)# so we could get an exact answer, but it will evaluate to about #4.6#, and dividing it by #2# would give us about #2.3#.

Hope this helps!