What is the equation of the line between #(0,0)# and #(2,-10)#?

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Answer 1 · 2018-04-29T13:28:41

The slope is -5.

To find this answer, we'll be using the point slope formula:

#(Y_2 - Y_1)/(X_2 - X_1) = m# , where #m# is the slope.

#(0, 0)# #(X_1, Y_1)#
#(2, 10)# #(X_2, Y_2)#

Now, plug-in the variables:

#(-10 - 0)/(2-0)# = #m#

Subtract.

#-10/2# = #m#

Simplify.

#-5/1# = #m#

The slope is #-5#.

#(y = -5x)#

Answer 2 · 2018-04-29T14:04:47

#y=-5x#

Slope-intercept form of an equation: #y=mx+b#, where #m# is the slope and #b# is the y-intercept

Let's first find the slope using the points #(x_1, y_1)# and #(x_2, y_2)#: #(y_2-y_1)/(x_2-x_1)#

#(-10-0)/(2-0)#

#(-10)/2#

#-5#

Our equation is currently #y=-5x+b#

The y-intercept is in the format #(0, b)#. The point #(0, 0)# is the y-intercept in this case.

#y=-5x+0#

#y=-5x#