Question

How do you find the axis of symmetry and vertex point of the function: `f(x) = -3x^2 - 6x + 4`?

Answer 1

Line x=-1

(-1,7)

Explanation:

`-b/[2a]` gives you the `x` coordinate for both.

`=> - [-6]/[2xx-3]`=-1

Substitute x=-1 into `-3x^2-6x+4` to find `y`

`=> -3xx(-1)^2-6xx-1+4`

`=> -3+6+4=7`