How do you solve #4m ^ { 2} + 76= 0#?

1 Answer
Jim G.
Apr 30, 2018

#m=+-sqrt19i#

Explanation:

#"subtract 76 from both sides"#

#rArr4m^2=-76#

#"divide both sides by 4"#

#rArrm^2=-19#

#"since - 19 there are no real roots instead there are"#
#"2 complex roots"#

#m^2=-19rArrm=+-sqrt19#

#rArrm=+-sqrt(19xx-1)=sqrt19xxsqrt-1=+-sqrt19i#

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