How many litres of liquid CCl4 ( d=1.5 g/cc) must be measured out to contain 10^25 CCl4 molecules?

1 Answer
Al E.
Apr 30, 2018

Let's use stoichiometry!

It's easier to think about if you focus on one relationship at a time.

#1.0*10^25"molecules" * "mol"/(6.02*10^23"molecules") * (154"g")/(C Cl_4) * ("cm"^3)/(1.5"g") * "mL"/"cm"^3 * "L"/(10^3"mL") approx 1.7"L"#

of one molar carbon tetrachloride solution must be measured out to "contain" that many molecules, given your data.

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