How many litres of liquid CCl4 ( d=1.5 g/cc) must be measured out to contain 10^25 CCl4 molecules?

1 Answer
Al E.
Apr 30, 2018

Let's use stoichiometry!

It's easier to think about if you focus on one relationship at a time.

#1.0*10^25"molecules" * "mol"/(6.02*10^23"molecules") * (154"g")/(C Cl_4) * ("cm"^3)/(1.5"g") * "mL"/"cm"^3 * "L"/(10^3"mL") approx 1.7"L"#

of one molar carbon tetrachloride solution must be measured out to "contain" that many molecules, given your data.

Related questions
Impact of this question
5183 views around the world
You can reuse this answer
Creative Commons License