Given: #log_b(4) = r#, #log_b(2) = t#, #log_b(3) = p# Find: #log_b(54) = # ?

1 Answer
May 1, 2018

#log_b54=t+3p=r/2+3p#

Explanation:

.

#log_b4=r, :. log_b2^2=r, :. 2log_b2=r, :. log_b2=r/2#

#log_b2=t=r/2#

#log_b3=p#

#log_b54=?#

#log_b54=log_b((2)(27))=log_b((2)(3)^3)=log_b2+log_b3^3=log_b2+3log_b3=t+3p=r/2+3p#