Question

What is the equation of sinusoidal function with the amplitude 3 and period pi/4?

Answer 1

`y=3sin(8x)`

Explanation:

The parent function is `sinx` so this is where we start.

`y=sinx`

The amplitude of this sine wave is 1. To make the amplitude 3, we multiply the sine by 3.

`y=3sinx`

The period of this sine wave is 2`pi`. We want the period to be `2pi/8` so we need to multiply `x` by 8.

`y=3sin(8x)`

This satisfies the requirements of the problem statement.

graph{3sin(8x) [-1, 1, -5, 5]}