How do you factor this equation #7x^{2} + 45x - 64= 0#?

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Answer 1 · 2018-05-02T11:46:01

the equation can be solved but not factored with rotational numbers

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#ax^{2} + bx + c= 0#

#x=[-b+-sqrt(b^2-4ac)]/2a#

#7x^{2} + 45x - 64= 0#

#a=7 and b=45 and c=-64#

#x=[-45+-sqrt(2025+1792)]/14#

#x=[-45+-sqrt(3817)]/14#

the equation can be solved but not factored with rotational numbers

search in wikipedia what mean of Rotation_number
https://en.wikipedia.org/wiki/Rotation_number