How do you solve #ln [((x+1) / x)]=1#?
1 Answer
May 2, 2018
# x = 1/(e-1) #
Explanation:
We have:
# ln((x+1)/x) = 1 #
Therefore, by the definition of the logarithm, we have:
# (x+1)/x = e #
Which we now solve for
# x+1 = ex #
# :. (e-1)x = 1 #
Giving the solution:
# x = 1/(e-1) #
