Question

If sides A and B of a triangle have lengths of 1 and 2 respectively, and the angle between them is `(5pi)/8`, then what is the area of the triangle?

Answer 1

A = 0.924 `units^2`

Explanation:

Remember that the equation for finding the area of a triangle is
1/2 ab sinC
So in this case the area is equal to: 1/2x1x2xsin(5`pi`/8)
Which simply becomes sin(5`pi`/8) (remember to have your calculator in radians mode)

Answer 2

`color(crimson)(A_t = 0.9239 " sq units"`

Explanation:

Formula for area of triangle = (1/2) b c sin A, knowing two sides and the included angle.

`b = 1, c = 2, hat A = (5pi)/8`

`"Area of Triangle " A_t = cancel(1/2) * 1 * cancel2 * sin ((5pi)/8)`

`color(crimson)(A_t = sin ((5pi)/8) = 0.9239 " sq units"`