What is #5y+x^2-:2# when #x=4# and #y=-3#?

1 Answer
May 3, 2018

-7.

Explanation:

Input all values into the equation.
#(5 * -3) + (4^2) / 2 #
we find this using PEMDAS
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction.

We find the exponent first, and #4^2# is 16. Next is multiplication/divison. 16 divided by 2 is 8. We also multiply 5(-3) at this point.
The resulting equation is -15+8, which is equal to -7