How do you solve # 4(b + 6) = 2(b + 5) + 2#?

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Answer 1 · 2018-05-04T22:19:14

#b=-6#

You distribute the #4# to the binomial of #(b+6)# and the #2# to the binomial of #(b+2)#

#4(b+6)=2(b+5)+2#

#4b+24=2b+10+2#
Combine any like terms

#4b+24=2b+12#
Subtract #12# from both sides.

#4b+12=2b#
Subtract #4b# from both side

#12=-2b#
Divide both sides by #-2#

#-6=b#

Check:

#4(-6 + 6)=2(-6+5)+2#
#4(0) = 2(-1)+2#
#0=-2+2#
#0=0#

This answer works.