Please solve q 6?

enter image source here

1 Answer
CW
May 5, 2018

#angleQSR=150^@#

Explanation:

enter image source here
Gien #AB=AC, => DeltaABC# is isosceles, #=> angleABC=angleACB=(180-110)/2=35^@#
given #DeltaAPC# is equilateral, #=> angleACP=60^@#
given #DeltaBRC# is equilateral, #=> angleBCR=angleBRC=60^@#,
consider #DeltaBQC, angleBQC=180-35-95=50^@#
given #SQ# bisects #angleBQC, => angleSQC=50/2=25^@#
similarly, given #SR# bisects #angleBRC, => angleSRC=60/2=30^@#
As #QSRC# is a quadrilateral,
#=> angleQSR=360-angleSRC-angleC-angleSQC#
#=> angleQSR=360-30-155-25=150^@#

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