What is the angular momentum of a rod with a mass of 8 kg8kg and length of 6 m6m that is spinning around its center at 9 Hz9Hz?

1 Answer
May 5, 2018

The angular momentum is=1357.2kgm^2s^-1=1357.2kgm2s1

Explanation:

The angular momentum is L=IomegaL=Iω

where II is the moment of inertia

The mass of the rod is m=8kgm=8kg

The length of the rod is L=6mL=6m

The moment of inertia of a rod, rotating about the center is

I=1/12*mL^2I=112mL2

=1/12*8*6^2= 24 kgm^2=112862=24kgm2

The angular velocity is

omega=2pif=2pixx9=18pirads^-1ω=2πf=2π×9=18πrads1

The angular momentum is

L=Iomega=24xx18pi=1357.2kgm^2s^-1L=Iω=24×18π=1357.2kgm2s1