Question

How do you solve the following system: #-6x + y = -8, 6y + 4x = 12 #?

Answer 1

`y=1`
`x=3/2`

Explanation:

`-6x+y=-8` --- (1)
`6y+4x=12` --- (2)

From (1),
`-6x+y=-8`
`y=6x-8` --- (3)

Sub (3) into (2)
`6(6x-8)+4x=12`
`36x-48+4x=12`
`40x=60`
`x=3/2` --- (4)

Sub (4) into (3)
`y=6*3/2-8`
`y=1`