How do you factor -3x^2+2x+2?

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Answer 1 · 2018-05-05T13:23:54

#-(3x^2-2x-2)#

#-3x^2+2x+2#

Factor the negative out,

#-(3x^2-2x-2)#

Answer 2 · 2018-05-05T13:25:56

#(x+(1-sqrt7)/3)(x+(1+sqrt7)/3)#

#-3x^2+2x+2#

Using the quadratic formula given by:

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Since the equation is in the general form #ax^2+bx+c# where #a=-3#, #b=2# and #c=2#

#x=(-2+-sqrt(4+24))/(-6#

#x=(-2+-sqrt28)/-6#

#x=(-2+-2sqrt7)/-6#

#x=(-1+-sqrt7)/-3#

Therefore,

#(x-((-1+sqrt7)/-3))(x-((-1-sqrt7)/-3))#

= #(x-(-1)(1-sqrt7)/3)(x-(-1)(1+sqrt7)/3)#

= #(x+(1-sqrt7)/3)(x+(1+sqrt7)/3)#