Solve for x: (X+2)^2=x^2+4x+4?

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Answer 1 · 2018-05-05T13:23:06

#x in RR#

#(x+2)^2=x^2+4x+4#

Factor right side,

#(x+2)^2=(x+2)^2#

Square root both sides,

#x+2=x+2#

Move like-terms together,

#x-x=2-2#

Simplify,

#0x=0#

Since, both sides are similar, we can denote that,

#x in RR#

Answer 2 · 2018-05-05T13:54:14

see a process solution step below;

#(x + 2)^2 = x^2 + 4x + 4#

factoring the right hand side..

#x^2 + 4x + 4 = (x + 2) (x + 2) #

#x^2 + 4x + 4 = (x + 2)^2#

therefore;

#(x + 2)^2 = (x + 2)^2#

#(x + 2)^cancel2 = (x + 2)^cancel2#

#x + 2 = x + 2#

collecting like terms..

#x - x = 2 - 2#

#0x = 0#

Hence;

#x in RR#