Question

What is the area of a triangle with sides of length 2, 6, and 9?

Answer 1

You cannot make a triangle with these three lengths.

Explanation:

Use Heron's formula where `A=sqrt(s(s-a)(s-b)(s-c))`
`a,b and c` are the three sides and `s=[a+b+c]/2`

`s=[2+6+9)/2`=8.5

`A=sqrt(8.5(8.5-2)(8.5-6)(8.5-9))`

`A=sqrt(8.5xx6.5xx2.5xx-0.5)`

`A=sqrt(-69.0625)`
Cannot take the square root of a negative number.